Posted by Lucas du Croo de Jongh on June 03, 1998 at 11:24:51:
In Reply to: Solving matrix eqn. Ax = 0 posted by Chris on April 07, 1998 at 17:28:23:
: I am interested in any routines which can "solve" the matrix eqn. Ax = 0 (A is a singular N by N matrix and x is an N element vector). In my case A is also symmetric, if that is any help.
(I suppose this is the way te reply to questions)
Ax=0
If A is positive definite you can minimize
xAx/(xx)
for instance by conjugate gradient (described in 'numerical recipes' section 10.6)
Otherwise you can of course minimize
xAAx/(xx)
but this will be quite slow.
cheers,
Lucas