c fishpk32 from portlib 12/30/83 c c * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * c * * c * f i s h p a k * c * * c * * c * a package of fortran subprograms for the solution of * c * * c * separable elliptic partial differential equations * c * * c * (version 3.1 , october 1980) * c * * c * by * c * * c * john adams, paul swarztrauber and roland sweet * c * * c * of * c * * c * the national center for atmospheric research * c * * c * boulder, colorado (80307) u.s.a. * c * * c * which is sponsored by * c * * c * the national science foundation * c * * c * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * c c program to illustrate the use of hstcyl to solve the equation c c (1/r)(d/dr)(r*du/dr) + (d/dz)(du/dz) = (2*r*z)**2*(4*z**2 + 3*r**2) c c on the rectangle 0 .lt. r .lt. 1 , 0 .lt. z .lt. 1 with the c boundary conditions c c (du/dr)(1,z) = 4*z**2 for 0 .le. z .le. 1 c c and c c (du/dz)(r,0) = 0 and (du/dz)(r,1) = 4*r**2 for 0 .le. r .le. 1 . c c the solution to this problem is not unique. it is a c one-parameter family of solutions given by c c u(r,z) = (r*z)**4 + arbitrary constant . c c the r-interval will contain 50 unknowns and the z-interval will c contain 52 unknowns. c dimension f(51,52) ,bdb(52) ,bdc(50) ,bdd(50) , 1 w(1108) ,r(50) ,z(52) c c from dimension statement we get value of idimf. also note that w c is dimensioned (13 + int(log2(n)))*m + 4*n . c idimf = 51 a = 0. b = 1. m = 50 mbdcnd = 6 c = 0. d = 1. n = 52 nbdcnd = 3 elmbda = 0. c c generate and store grid points for the purpose of computing c boundary data and the right side of the poisson equation. c do 101 i=1,m r(i) = (float(i)-0.5)/50. 101 continue do 102 j=1,n z(j) = (float(j)-0.5)/52. 102 continue c c generate boundary data. c do 103 j=1,n bdb(j) = 4.*z(j)**4 103 continue do 104 i=1,m bdc(i) = 0. bdd(i) = 4.*r(i)**4 104 continue c c bda is a dummy variable. c c generate right side of equation. c do 106 i=1,m do 105 j=1,n f(i,j) = 4.*r(i)**2*z(j)**2*(4.*z(j)**2+3.*r(i)**2) 105 continue 106 continue call hstcyl (a,b,m,mbdcnd,bda,bdb,c,d,n,nbdcnd,bdc,bdd,elmbda,f, 1 idimf,pertrb,ierror,w) c c compute discretization error by minimizing over all a the function c norm(f(i,j) - a*1 - u(r(i),z(j))). the exact solution is c u(r,z) = (r*z)**4 + arbitrary constant. c x = 0. do 108 i=1,m do 107 j=1,n x = x+f(i,j)-(r(i)*z(j))**4 107 continue 108 continue x = x/float(m*n) do 110 i=1,m do 109 j=1,n f(i,j) = f(i,j)-x 109 continue 110 continue err = 0. do 112 i=1,m do 111 j=1,n x = abs(f(i,j)-(r(i)*z(j))**4) if (x .gt. err) err = x 111 continue 112 continue print 1001 , ierror,pertrb,err,w(1) stop c 1001 format (1h1,20x,25hsubroutine hstcyl example/// 1 10x,46hthe output from the ncar control data 7600 was// 2 32x,10hierror = 0/32x,20hpertrb =-4.43114e-04/ 3 18x,34hdiscretization error = 7.52796e-05/ 4 12x,32hrequired length of w array = 958// 5 10x,32hthe output from your computer is// 6 32x,8hierror =,i2/32x,8hpertrb =,e12.5/ 7 18x,22hdiscretization error =,e12.5/ 8 12x,28hrequired length of w array =,f4.0) c end